Teh sum of ages of 7 children born at the interval of 2 years is 49years. Find the age of the youngest one..
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♠ Let the ages of children be x, x + 2, x + 4, x + 6, x + 8, x + 10 and x + 12.
♠ Give that the sum of their ages = 49
→→→ x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 + x + 12 = 49
=> 7x + 42 = 49
=> 7x = 49 - 42
=> 7x = 7
=> x = 7/7
=> x = 1
•°• The ages -
x = 1
x + 2 = 3
x + 4 = 5
x + 6 = 7
x + 8 = 9
x + 10 = 11
x + 12 = 13.
♠ Out of them, the youngest is of 1 years.
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