Math, asked by 1113994, 6 hours ago

Telegraph pole occurs at equal distances of 220m along a road and heaps of stones are put at equal distances of 300m along the same road. The first heap is at the foot of the first pole. How far from it along the road is the next heap which lies at the foot of a pole.

Answers

Answered by YourHelperAdi

Step-by-step explanation:

Distance between each pole = 220m

Distance between each heap = 300m

so to find the next point at which the heap would be at foot of pole , we have to find L.C.M of 220m and 300m

so, L.C.M of 220m and 300m = 3300m

so they will meet after 3300m

that is 3.3 km

Answered by nutansingh1405

Step-by-step explanation:

220 = 2 × 2 × 5 × 11

300 = 2 × 2 × 3 × 5 × 5

So the required LCM = 2 × 2 × 3 × 5 × 5 × 11 = 3300

Therefore, the next heap which lies at the foot of a pole is 3300m far along the road.

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Telegraph pole occurs at equal distances of 220m along a road and heaps of stones are put at equal distances of 300m along the same road. The first heap is at the foot of the first pole. How far from it along the road is the next heap which lies at the foot of a pole.​

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Telegraph pole occurs at equal distances of 220m along a road and heaps of stones are put at equal distances of 300m along the same road. The first heap is at the foot of the first pole. How far from it along the road is the next heap which lies at the foot of a pole.