Math, asked by awunirichmond60, 3 months ago

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${x}^{2} - x + 1 = 0$

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Answered by cutekamini01

Step-by-step explanation:

x^2-x+1=0

x(x-1)-1(x-1)=0

x-1=0

x=1 is the correct answer

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TELEO
${x}^{2} - x + 1 = 0$