Telephone pole are fixed at an equal distance from each other if 12 such Pole are fixed over a month of 75km how many pole are required for a distance of 25km? isko solve karna hai
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let the point where it broke be B.
the base be C.
the fallen top be A.
ABC form right triangle where angle c is 90.
AC is 5m.
BC is 12 m.
by pythagoras theorem,
AB2 = BC2 + AC2
AB2 = 12square + 5square
AB2 = 144 + 25
AB2 = 169
Ab = 13
total height of pole before breaking = 12m + 13m
=25m
the base be C.
the fallen top be A.
ABC form right triangle where angle c is 90.
AC is 5m.
BC is 12 m.
by pythagoras theorem,
AB2 = BC2 + AC2
AB2 = 12square + 5square
AB2 = 144 + 25
AB2 = 169
Ab = 13
total height of pole before breaking = 12m + 13m
=25m
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