Question

TELL 9TH AND 10TH ANSWER​

Answer 1

Answer:

1/(a+b+x)=1/a + 1/b + 1/x

1/(a+b+x) -1/x = 1/a + 1/b

x-(a+b+x)/x(a+b+x) = a+b/ ab

-1(a+b) /x(a+b+x) = a+b/ ab

-1(a+b)/(a+b) = x(a+b+x)/ab

-1=x(a+b+x) / ab

-ab= (a+b)x + x2

x2 + (a+b)x +ab =  0

now, A = 1,  B=(a+b) C= ab..

so, D = B2 - 4AC

 =(a+b)2 - 4ab

 = (a-b)2

so, x = (-B + √ D)/2A  and (-B-√ D)/2A

 = -a-b+a-b /2*1   and  -a-b-a+b /2*1

 = -2b/1  and -2a /1

so,x = -2b or -2a .

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10th....

4x^2 - 4a^2x + (a^4 - b^4) = 0

4x^2 - 4a^2x + (a^2 - b^2) (a^2 + b^2) = 0

4x^2 - 2(a^2 + b^2)x -2(a^2 - b^2)x + (a^2 - b^2) (a^2 + b^2) = 0

2x [ 2x - (a^2 + b^2) ] - (a^2 - b^2) [ 2x - (a^2 + b^2) ] = 0

x= a^2+b^2/2

or

x=a^2-b^2/2

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Answer 2

Your answer is above please refer to it .

Hope it helps you

thanks