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Answer:Taking x= 2^(2/3) + 2 ^(1/3) we get x = (cube root of 2)^2 + (cube root of 2) [ Because power 1/3 is nothing but cube ...
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\sum\limits_{i=1}^n x_i = x_1 + x_2 + \dots + x_n
i = index of summation.
n = upper limit of summation
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