Question

Tell ans pls i want to know how it is done​

Answer 1

Answer:

what your questions pls tell us

Answer 2

Answer:

Step-by-step explanation:

Given: ∠EGF = 37°, ∠GOF = 90° ( Diagonals of a rhombus perpendicularly bisect each other. )

Therefore,

∠OFG + ∠OGF + ∠GOF = 180° ( ANGLE SUM PROPERTY OF A TRIANGLE)

∠OFG + 37 + 90 = 180

∠OFG = 180 - 127 = 53°

∠EFG + ∠FGH = 180° ( ADJACENT ANGLES OF A PARALELLOGRAM )

∠FGH  = 180 - 70 = 110°

∠FGH = ∠EGH + ∠EGF

110 = ∠EGH + 37

∠EGH = 110 - 37 = 73

THEREFORE,

IN TRIANGLE OGH,

∠FHG + ∠OGH + ∠HOG = 180°

∠FHG + 73 + 90 = 180

∠FHG  = 180 - 163 = 17