Question

Tell answer to this question :-
If 21y5 is a multiple of 9,where y is a digit, what is the value of y?​

Answer 1

Required answer:- 1

Solution:-

Since the number 21y5 is a multiple of 9.

So, the sum of its digits 2+1+y+5=8+y is a multiple of 9.

∴(8+y) is either 0 or 9 or 18 or ...

Since y is a digit, so (8+y) must be equal to 9.

i.e., 8+y=9

⇒y=9−8=1