Question

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Answer 1

Answer:

Question-

The area of a square is the same as of a rectangular park. If the side of the square is 60m and the length of the rectangular park is 90m, find the breadth of the rectangle.

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Answer-

$\rightarrow$ Finding area of the square with the side 60m is the first step.

$\color{black}\boxed{\colorbox{saffron}{Area - side×side}}$

$60 \times 60 \\ \\ = {3600m}^{2}$

In the question, it is mention that the area of the square is same as the area of rectangle.

So,

Area of rectangular park = ${3600m}^{2}$

Length =90m

Breadth = x

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$\rightarrow$ Let now find the breadth of the rectangular park.

$\color{black}\boxed{\colorbox{saffron}{Area - length×breadth}}$

${3600}^{2} = {90}^{2} \times {x}^{2} \\ \\ = \frac{3600}{90} = x \\ \\ = 40 = x$

So, breadth= 40m

Step-by-step explanation:

Required Answer-

$\rightarrow$ Breadth = 40m

Answer 2

Given : The area of a square park is the same as of a rectangular park. Side of the square park is 60m and length of the rectangular park is 90m.

To Find : Breadth of the rectangular park.

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Here

$\:$

• Side of the square park = 60m
• Length of the rectangular park = 90m

$\:$

Firstly we'll find the area of the square park.

$\: \:$

As we know that :

$\:$

$\underline{\boxed{\sf\purple{\bigstar \: area \: of \: a \: square \: = {side}^{2} }}}$

$\:$

Now we'll put the value of side of the park which is in the form of a square.

$\:$

$\sf:\implies \: area \: of \: the \: square \: park = {side}^{2} \\ \\ \\ \sf:\implies \: area \: of \: the \: square \:park = {(60)}^{2} \\ \\ \\ \sf:\implies \: area \: of \: the \: square \: park= 60 \times 60 \\ \\ \\ \sf:\implies \: area \: of \: the \: square \: park= \underline{\boxed{\sf\purple{3600 {m}^{2} }}}\bigstar$

$\:$

$\because \: \sf \: Area \: of \: the \: square \: park = Area \: of \: the \: rectangular \: park$

$\:$

As we know that :

$\: \:$

$\underline{\boxed{\sf\purple{\bigstar \: area \: of \: a \: rectangle \: = l \times b}}}$

$\:$

Where

$\:$

• l = length
• b = breadth

$\:$

We'll put the values of area and length of the park which is in the form of a rectangle.

$\:$

$\sf:\implies \: area \: of \: the \: rectangular \: park = l \times b \\ \\ \\ \sf:\implies \: 3600 = 90 \times b \\ \\ \\ \sf:\implies \: b = \cancel \frac{3600}{90} \\ \\ \\ \sf:\implies \: b =\underline{\boxed{\sf\purple{40m}}} \bigstar \\ \\ \\ \\ \sf\therefore{\underline{Hence, \: the \: breadth \: of \: the \: rectangular \: park \: is \: \bold{40m}.}}$