Math, asked by mohiniparth, 10 months ago

tell fast that 4(2X-1)-2(X-5)=5(X+1)+3 solve​

Answers

Answered by tomboy4
1

Answer:

2

Step-by-step explanation:

the answer is in the attachment

Attachments:
Answered by AbhijithPrakash
5

Answer:

4\left(2X-1\right)-2\left(X-5\right)=5\left(X+1\right)+3\quad :\quad X=2

Step-by-step explanation:

4\left(2X-1\right)-2\left(X-5\right)=5\left(X+1\right)+3

\black{\mathrm{Expand\:}4\left(2X-1\right)-2\left(X-5\right):}

4\left(2X-1\right)-2\left(X-5\right)

\gray{\mathrm{Expand}\:4\left(2X-1\right):\quad 8X-4}

=8X-4-2\left(X-5\right)

\gray{\mathrm{Expand}\:-2\left(X-5\right):\quad -2X+10}

=8X-4-2X+10

\gray{\mathrm{Simplify}\:8X-4-2X+10:\quad 6X+6}

=6X+6

\black{\mathrm{Expand\:}5\left(X+1\right)+3:}

5\left(X+1\right)+3

\gray{\mathrm{Expand}\:5\left(X+1\right):\quad 5X+5}

=5X+5+3

\gray{\mathrm{Add\:the\:numbers:}\:5+3=8}

=5X+8

6X+6=5X+8

\gray{\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}}

6X+6-6=5X+8-6

\gray{\mathrm{Simplify}}

6X=5X+2

\gray{\mathrm{Subtract\:}5X\mathrm{\:from\:both\:sides}}

6X-5X=5X+2-5X

\gray{\mathrm{Simplify}}

X=2

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