Question

tell how to do this.....​

Answer 1

Step-by-step explanation:

we know that nCr is equal to n!/r!*(n-r)!

soo 11C0 is equal too 11!/0!*(11-0)!=1

similarly,11C1=11!/1!*(11-1)!=11

11C2=11!/2!*(11-2)!=11*10/2=55,

11C3=11*10*9/(3*2)=165

11C4=11*10*9*8/(4*3*2)=330

11C5=11*10*9*8*7/(5*4*3*2)=462

add them we get

1+11+55+165+330+462

ans is 1024