Math, asked by Anonymous, 7 months ago

tell important formulas in trigonometry
for class 10
no spamming​

Answers

Answered by vasundhrakrishnar
3

Answer:

Trigonometry is the study of relationships between angles, lengths, and heights of triangles. It includes ratios, function, identities, formulas to solve problems based on it, especially for right-angled triangles. Applications of trigonometry are also found in engineering, astronomy, Physics and architectural design. This chapter is very important as it comprises many topics like Linear Algebra, Calculus and Statistics.

Trigonometry is introduced in CBSE class 10. It is a completely new and tricky chapter where one needs to learn all the formula and apply them accordingly. Trigonometry Class 10 formulas are tabulated below.

List of Trigonometric Formulas for 10th

Trigonometry Formulas for Class 10

Applying Pythagoras theorem for the given right-angled triangle, we have:

(Perpendicular)2+(Base)2=(Hypotenuse)2

⇒(P)2+(B)2=(H)2

The Trigonometric formulas are given below:

S.no Property Mathematical value

1 sin A Perpendicular/Hypotenuse

2 cos A Base/Hypotenuse

3 tan A Perpendicular/Base

4 cot A Base/Perpendicular

5 cosec A Hypotenuse/Perpendicular

6 sec A Hypotenuse/Base

Reciprocal Relation Between Trigonometric Ratios

S.no Identity Relation

1 tan A sin A/cos A

2 cot A cos A/sin A

3 cosec A 1/sin A

4 sec A 1/cos A

Trigonometric Sign Functions

sin (-θ) = − sin θ

cos (−θ) = cos θ

tan (−θ) = − tan θ

cosec (−θ) = − cosec θ

sec (−θ) = sec θ

cot (−θ) = − cot θ

Trigonometric Identities

sin2A + cos2A = 1

tan2A + 1 = sec2A

cot2A + 1 = cosec2A

Periodic Identities

sin(2nπ + θ ) = sin θ

cos(2nπ + θ ) = cos θ

tan(2nπ + θ ) = tan θ

cot(2nπ + θ ) = cot θ

sec(2nπ + θ ) = sec θ

cosec(2nπ + θ ) = cosec θ

Complementary Ratios

Quadrant I

sin(π/2−θ) = cos θ

cos(π/2−θ) = sin θ

tan(π/2−θ) = cot θ

cot(π/2−θ) = tan θ

sec(π/2−θ) = cosec θ

cosec(π/2−θ) = sec θ

Quadrant II

sin(π−θ) = sin θ

cos(π−θ) = -cos θ

tan(π−θ) = -tan θ

cot(π−θ) = – cot θ

sec(π−θ) = -sec θ

cosec(π−θ) = cosec θ

Quadrant III

sin(π+ θ) = – sin θ

cos(π+ θ) = – cos θ

tan(π+ θ) = tan θ

cot(π+ θ) = cot θ

sec(π+ θ) = -sec θ

cosec(π+ θ) = -cosec θ

Quadrant IV

sin(2π− θ) = – sin θ

cos(2π− θ) = cos θ

tan(2π− θ) = – tan θ

cot(2π− θ) = – cot θ

sec(2π− θ) = sec θ

cosec(2π− θ) = -cosec θ

Sum and Difference of Two Angles

sin (A + B) = sin A cos B + cos A sin B

sin (A − B) = sin A cos B – cos A sin B

cos (A + B) = cos A cos B – sin A sin B

cos (A – B) = cos A cos B + sin A sin B

tan(A+B) = [(tan A + tan B)/(1 – tan A tan B)]

tan(A-B) = [(tan A – tan B)/(1 + tan A tan B)]

Double Angle Formulas

sin2A = 2sinA cosA = [2tan A + (1+tan2A)]

cos2A = cos2A–sin2A = 1–2sin2A = 2cos2A–1= [(1-tan2A)/(1+tan2A)]

tan 2A = (2 tan A)/(1-tan2A)

Thrice of Angle Formulas

sin3A = 3sinA – 4sin3A

cos3A = 4cos3A – 3cosA

tan3A = [3tanA–tan3A]/[1−3tan2A

Step-by-step explanation:

p

PLEASE MARK ME AS BRAINIEST

Similar questions