Question

tell me about this please ​

Answer 1

Answer:

it is very easy but i dont want to ans

Answer 2

Answer:

Solution:- (A) one solution

For the given pair of equations x−2y=0 and 3x+4y=20;

a2a1=31

c2b1=4−2=2−1

c2c1=−200=0

As the given pair of linear equation satisfies a2a1=b2b1,

The graph will be a pair of lines intersecting at a unique point, which is the solution of the pair of equations.