Question

tell me answer me please ​

Answer 1

$\Huge\boxed{x = \frac{1}{ \sqrt{7} } }$$\LARGE{ \: or \: }$$\Huge\boxed{x = - \frac{ \sqrt{7} }{3} }$

Answer:

We have,

$3 \sqrt{7} {x}^{2} + 4x - \sqrt{7} = 0$

$3 \sqrt{7} {x}^{2} + (7 - 3)x - \sqrt{7} = 0$

$3 \sqrt{7} {x}^{2} + 7x - 3x - \sqrt{7} = 0$

$3 \sqrt{7} {x}^{2} - 3x + 7x - \sqrt{7} = 0$

$3x( \sqrt{7} x) - 3x(1) + \sqrt{7} ( \sqrt{7} x) - \sqrt{7} (1) = 0$

$3x( \sqrt{7} - 1) + \sqrt{7} ( \sqrt{7} x - 1) = 0$

$( \sqrt{7} x - 1)(3x + \sqrt{7} ) = 0$

$\large\boxed{x = \frac{1}{ \sqrt{7} } }$ or $\large\boxed{x = - \frac{ \sqrt{7} }{3} }$