Question

tell me answer of this​

Answer 1

Answer:

{given that x+y=8 and x^2+y^2=28}

x^3+y^3=(x+y)(x^2-xy+y^2)

x^3+y^3=8*(28-xy)

x^3+y^3=224-8xy

Now for xy,

(x+y)^2=x^2+xy+y^2

putting values,

8^2=28+xy

64=28+xy

xy=64-28=18

Now going back,

x^3+y^3=224-8(18)

x^3+y^3=224-144=80

The answer is 80.