Math, asked by JaydeepsingPatil, 1 month ago

tell me answer quickly​

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Answered by abhinavmike85
23

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y = \dfrac{17}{15}\\\\

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 \dfrac{y - (7 - 8y)}{9y - (3 + 4y)} =  \dfrac{2}{3}   \\  \\  \dfrac{y - 7 + 8y}{9y - 3 - 4y}  =  \dfrac{2}{3}  \\

Cross multiplying we get:

3(9y - 7) = 2(5y - 3) \\  \\ 27y - 21 = 10y - 6 \\

Shifting y terms to LHS and constants to RHS,

27y - 10y = 21 - 6 \\  \\ 17y = 15 \\  \\ y =  \dfrac{17}{15}

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Answered by gufranaq1980
0

Answer:

3( y-7+8y) =2(9y-4-4y)

3(9y-7) =2(5y-4)

27y-21= 10y-8

27y-10y= 21-8

17y=13

y= 13/17 Ans

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