Question

tell me answer this question ​

Answer 1

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Answer 2

$\frac{ \tan(60)}{ \sin(60) + \cos(30) } \\ = > \frac{ \sqrt{3} }{ \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{2} } \\ = > \frac{ \sqrt{3} }{ \frac{ \sqrt{3} + \sqrt{3} }{2} } \\ = > \frac{ \sqrt{3} }{ \frac{2 \sqrt{3} }{2} } \\ = > \frac{ \sqrt{3} }{ \sqrt{3} } \\ = > 1$

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