Question

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Answer 1

When a die is rolled (or thrown), we get the outcomes as:

{1, 2, 3, 4, 5, 6}

That means, the total number of outcomes = n(S) = 6

Let E be the event of getting a multiple of 3.

E = {3, 6}

Number of favorable outcomes of the event E = n(E) = 2

P(E) = n(E)/n(S) = 2/6 = ⅓

Hence, the probability of getting a multiple of 3 when a die is thrown is 1/3.

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Answer 2

Answer:

When a die is rolled (or thrown), we get the outcomes as:

{1, 2, 3, 4, 5, 6}

That means, the total number of outcomes = n(S) = 6

Let E be the event of getting a multiple of 3.

E = {3, 6}

Number of favorable outcomes of the event E = n(E) = 2

P(E) = n(E)/n(S) = 2/6 = ⅓

Hence, the probability of getting a multiple of 3 when a die is thrown is 1/3.

Step-by-step explanation:

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