Question

Tell me correct answer with explanation​

Answer 1

CURRENT INCREASES 4 TIMES

V= IR

V=V/2

R=2R

V/2=I×2R

V=4IR

Answer 2

Current decreases 1/4 times as

I=V/R

Let V=1 and R =1, then

I=1/2/2×1

I=1/4

So the net current flow is decreased by 1/4.