tell me how to do the 8th one
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area of parallelogram ABCD = B*H (base * height )
let base be AB and height AE then area ⇒ 16 * 8
now when base is AD then height will be FC ⇒ AD * 10
since parallelogram is same therefore area will be same ⇒ 16*8 = AD*10
⇒128/10 = 12.8cm
let base be AB and height AE then area ⇒ 16 * 8
now when base is AD then height will be FC ⇒ AD * 10
since parallelogram is same therefore area will be same ⇒ 16*8 = AD*10
⇒128/10 = 12.8cm
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