Question

tell me how to solve it and what is the answer?

Answer 1

Given
1 step = 1 m
time for 1 step = 1sec
displacement
5 step forward , 3 step backwards
time of action = 8 sec
then minimum total displacement required
= 11 step
then
round 1
displacement = 5 - 3
= 2 step
time = 8 sec
round 2
displacement = 2+5-3
= 4 step
time = 16 sec
round 3
displacement
= 4+5-3
= 6
time = 24
now as
in round 3
he will move forward
5 steps then he will fall
and Time = 29 sec

hope it helps

Answer 2

Distance covered with 1 step = 1 m
Time taken = 1 s
Time taken to move first 5 m forward = 5 s
Time taken to move 3 m backward = 3 s
Net distance covered = 5 – 3 = 2 m
Net time taken to cover 2 m = 8 s
Drunkard covers 2 m in 8 s.
Drunkard covered 4 m in 16 s.
Drunkard covered 6 m in 24 s.
Drunkard covered 8 m in 32 s.
In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit.
Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s

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