Question

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Answer 1

ans:

ans: 1--i) 20+x=90

ans: 1--i) 20+x=90 x= 90-20

ans: 1--i) 20+x=90 x= 90-20 x = 70

ans: 1--i) 20+x=90 x= 90-20 x = 70 ii) 63+x= 90

ans: 1--i) 20+x=90 x= 90-20 x = 70 ii) 63+x= 90 x= 90-63

ans: 1--i) 20+x=90 x= 90-20 x = 70 ii) 63+x= 90 x= 90-63 x = 27

ans: 1--i) 20+x=90 x= 90-20 x = 70 ii) 63+x= 90 x= 90-63 x = 27 2--2x= 90

ans: 1--i) 20+x=90 x= 90-20 x = 70 ii) 63+x= 90 x= 90-63 x = 27 2--2x= 90 x= 90/2

ans: 1--i) 20+x=90 x= 90-20 x = 70 ii) 63+x= 90 x= 90-63 x = 27 2--2x= 90 x= 90/2 x = 45

ans: 1--i) 20+x=90 x= 90-20 x = 70 ii) 63+x= 90 x= 90-63 x = 27 2--2x= 90 x= 90/2 x = 453--i) angle 5 and angle 1

ans: 1--i) 20+x=90 x= 90-20 x = 70 ii) 63+x= 90 x= 90-63 x = 27 2--2x= 90 x= 90/2 x = 453--i) angle 5 and angle 1 ii) angle 4 and angle 1

Answer 2

Answer:

below is the answer ↓

Q1. i) complementary angles are always 90° so 90°-20°=70° ii) 90°-63°=27°

Q2. 45°, because 90°-45°=45° which are equal complements.

Q3. Vertically Opp. Angles: 1 and 4

Linear pair: 1 and 5, 4 and 3 and 2, 1 and 2 and 3, 5 and 4.

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