tell me some logic questions on maths with answers
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3
hey there,
Question 1: Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same point at 40 mph in the same direction as car A. At what time will car B pass car A?
Solution: Let after t hours the distances D1 traveled by car A
=> D1 = 30 t
Car B starts at 10 am and will therefore have spent one hour less than car A when it passes it.
After (t - 1) hours, distance D2 traveled by car B
=> D2 = 40 (t - 1)
When car B passes car A, they are at the same distance from the starting point and therefore D1 = D2
=> 30 t = 40 (t - 1)
Solve the equation for t,
=> 30 t = 40t - 40
=> 10 t = 40
=> t = 4
=> Car B passes car A at = 9 + 4 = 13 pm.
Another could be:
Question 2: Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.
Solution: First integer = x
Second integer = x + 2
Third integer = x + 4
Since four times the first integer equals six more than the product of two and the third integer.
=> 4x = 6 + 2(x + 4)
=> 4x = 6 + 2x + 8
=> 2x = 14
=> x = 7.
Hence,
First integer = x = 7
Second integer = x + 2 = 7 + 2 = 9
Third integer = x + 4 = 7 + 4 = 11.
Question 1: Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same point at 40 mph in the same direction as car A. At what time will car B pass car A?
Solution: Let after t hours the distances D1 traveled by car A
=> D1 = 30 t
Car B starts at 10 am and will therefore have spent one hour less than car A when it passes it.
After (t - 1) hours, distance D2 traveled by car B
=> D2 = 40 (t - 1)
When car B passes car A, they are at the same distance from the starting point and therefore D1 = D2
=> 30 t = 40 (t - 1)
Solve the equation for t,
=> 30 t = 40t - 40
=> 10 t = 40
=> t = 4
=> Car B passes car A at = 9 + 4 = 13 pm.
Another could be:
Question 2: Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.
Solution: First integer = x
Second integer = x + 2
Third integer = x + 4
Since four times the first integer equals six more than the product of two and the third integer.
=> 4x = 6 + 2(x + 4)
=> 4x = 6 + 2x + 8
=> 2x = 14
=> x = 7.
Hence,
First integer = x = 7
Second integer = x + 2 = 7 + 2 = 9
Third integer = x + 4 = 7 + 4 = 11.
Answered by
0
find the smallest +ve mathematical number which is spelled in an alphabetical order
ans-40
replace ? by mathematical symbol to make the equation true
18 ? 12 ? 4 ? 5 = 59
ans- 18*12/4+5=59
1pound=100penny
=10penny*10penny
=1/10pound*1/10pound
=1/100pound
=1penny
=>1pound=1penny
ans- step 3 is wrong
ans-40
replace ? by mathematical symbol to make the equation true
18 ? 12 ? 4 ? 5 = 59
ans- 18*12/4+5=59
1pound=100penny
=10penny*10penny
=1/10pound*1/10pound
=1/100pound
=1penny
=>1pound=1penny
ans- step 3 is wrong
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