Question

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Answer 1

2) reciprocal of $\frac{5}{129}$ =$\frac{129}{5}$

                            = $\frac{5}{129}$ ×$\frac{129}{5}$

                            =1

3)The first 10 odd natural numbers are 1, 3, 5, 7, 9, 11, 13, 15, 17, 19

The mean of the first 10 odd natural number is 10

mean = $\frac{sum of terms }{no.of terms}$= $\frac{1+3+5+7+9+11+13+15+17+19}{10}$

mean = $\frac{100}{10}$

median = 1, 3, 5, 7, 9, 11, 13, 15, 17, 19

since its even no. of terms will take mean of sum of middle terms

median =$\frac{9+11}{2}$

            =$\frac{20}{2}$

             =10

mode is the number occured most number of time

and here there is no repeated number so the mode is 0

4) p-5=2

   p=2+5

   p=7

           

Answer 2

Step-by-step explanation:

2).5/129×129/5=1

3)let, take 1-10 idd natural numbers

=1,3,5,7,9

=5 odd natural number

mean=sum of observation /number of ibservation

=1+3+5+7+9/5

=25/5

=5

median=middle term =5

mode =repeated numbers there is no repeated numbers so,mode=0

4)According to the ques ,p-5=2

p=-5-2

=-3

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