Chemistry, asked by chemicalreaction72, 1 year ago

tell me the answer of questions given in images : ​

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Answered by smartyyash7
1

\huge\mathfrak\red{Solution}

For the reaction equilibrium constant, Kg can be written as :

Kc = [NO]² / [N2][O2]

Kc = (2.8 * 10 to the power -3 M) ² / ( 3.0 * 10 to the power -3 M) ( 4.2 * 10 to the power -3 M)

Kc = 0.622

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Answered by Brainly9b78
0
For the reaction equilibrium constant, Kg can be written as :

Kc = NO² / N2 O2
Kc = (2.8 * 10 to the power -3 M) ² / ( 3.0 * 10 to the power -3 M) ( 4.2 * 10 to the power -3 M)
Kc = 0.622

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