Question

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Answer 1

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Answer 2

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Question:-

$rita \: has \: bougt \: a \: carpet \: of \: size \: 4m \times 6 \times \frac{1}{3} m \: but \: her \: room \: \: size \: is \: 3 \times \frac{1}{4} m \: \times 5 \times \frac{3}{4} m \: what \: fraction \: of \: area \: should \: be \: cut \: of \: to \: fit \: the \: carpet \: wall \: \: to \: wall \: in \: the \: room$

Answer:-

$given. \: \: \: carpet \: size = 4m \times 6 \times \frac{1}{3} m \: \: and \: \: \: room \: size = 3 \times \frac{1}{4} m \times 5 \times \frac{3}{4} m$

$area \: of \: carpet \: = 4 \times 6 \times \frac{1}{3} m {}^{2} = \frac{76}{3} m {}^{2}$

$area \: of \: room \: = 3 \times \frac{1}{4} \times 5 \frac{3}{4}m {}^{2} = \frac{13}{4} \times \frac{23}{4 } = \frac{299}{16} m {}^{2}$

$area \: needed \: to \: be \: cut \: = \frac{76}{3} - \frac{299}{16} = \frac{76 \times 16 - 299 \times 3}{48} m {}^{2} = \frac{319}{48} m {}^{2}$

$fraction \: of \: area \: cut \: out \: is \: = \frac{319}{48} \times \frac{3}{76} = \frac{319 \times 3}{48 \times 76} = \frac{319}{1216}$

$hene \: \frac{319}{1216} \: part \: of \: carpet \: should \: be \: cut \: out \: to \: bit \: into \: room$