Question

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Answer 1

Answer:

In triangle PQR and triangle PSR

PQ=PS(S)

<QPR=<RPS(A)

PR=PR(S)

By S. A. S PQR=~ to PSR

By C. P. C. T QR=SR

I hope my answer helps you

Answer 2

Step-by-step explanation:

Given: PQ=PS

           <1=<2

To Prove: Triangle PQR≅PSR

                 QR=SR

To Proof: In Triangle PQR and PSR

           PQ=PS(given)

           <1=<2(given)

           PR=PR(common)

Therefore, by S-A-S RULE Triangle PQR≅PSR.

Also, by C.P.C.T.

    QR=SR