Math, asked by devum12, 11 months ago

tell me the answer tell me fast​

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Answered by syedsaifullah024
1

When the police starts the chase, the thief would have ran 100m due to the 2 min delay.

Distance of thief from the theft location after :

1 min 2 min 3 min 4 min 5 min 6 min 7 min

50m 100m 150m 200m 250m 300m 350m

Distance of police from the theft location after:

1 min 2 min 3 min 4 min 5 min 6 min 7 min

0m 0m 60m 125m 195m 270m 350m

The distance of the thief and police from the theft scene becomes equal after 7 min. The distance of the thief increases by 50m per min because he is running at the rate of 50m per min. The distance of the police is 0m for the first 2 min because he starts the chase after 2 min. And the distance of the police starts as 60m at the first min of his run and gradually increases by 65m, 70m, 75m and 80m.

Thus the police catches the thief after 7 min.

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