Question

Tell me the area of PQR with steps. Answer only if you know otherwise I will Report it. ​

Answer 1

The area of the triangle PQR is 120 cm²

Step-by-step explanation:

I guessed the question to be in complete. With little research I found the attached image where the length of the side QR is also given

In ΔPMR

∵ ∠PMR is is right angle

∴ By Pythagoras Theorem

$PR^2=PM^2+MR^2$

$\implies PR^2=6^2+8^2$

$\implies PR^2=36+64$

$\implies PR^2=100$

$\implies PR=\sqrt{100}$

$\implies PR=10$ cm

Now, in right angled ΔQPR

$PQ^2+PR^2=QR^2$

$\implies PQ^2+10^2=26^2$

$\implies PQ=676-100$

$\implies PQ=576$

$\implies PQ=\sqrt{576}$

$\implies PQ=24$ cm

Therefore, the area of the triangle

$A=\frac{1}{2}\times PQ\times PR$

$\implies A=\frac{1}{2}\times 24\times 10$

$\implies A=120$ cm²

Hope this answer is helpful.

Know More:

Q: In figure the area of triangle ABC in square units is:

Click Here: https://brainly.in/question/5597824

Answer 2

$\huge\bold\green {Answer}$

According to the question we have given that :-

•°• PM = 6 cm

•°• MR = 8 cm

So, as said in question we have to find Area of PQR

Now , In ΔPMR :-

∠RMP is is right angle [ 90° ]

So, by using By Pythagoras Theorem we get :-

•••→ PR²=PM²+MR²

Now , by substituting the known values in formula

•••→ PR² = 6² + 8²

•••→ PR² = 36 + 64

•••→ PR² = 100

•••→ PR = 10 cm

Now, in right angled ΔRPQ again we apply Pythagoras theorem :-

•••→ PQ² + PR² = QR²

Now by substituting the known values in formula we get :-

•••→ PQ² + 10² = 26²

•••→ PQ² = 676 - 100

•••→ PQ² = 576

•••→ PQ = 24 cm

Hence, according to the , the area of the triangle

•••→ $\sf\orange{Area =\frac{1}{2}\times PQ\times PR}$

Now, by substituting the known values in formula we get :-

•••→ $\sf{Area=\frac{1}{2}\times 24\times 10}$

•••→ Area = 120 cm²

Hence the required area is 120 cm²