Question

tell me the fourth question of this
it's of chapter number 14 class 8 factorization

Answer 1

$20 {x}^{2} - 45 {y}^{2} \\ ({2 \sqrt{5}x) }^{2} - ( {3 \sqrt{5}y) }^{2} using the identity a^2 - b^2 = (a+b)(a-b)\\ (2 \sqrt{5} x - 3 \sqrt{5} y)(2 \sqrt{5} x + 3 \sqrt{5} y)$
hope it helps u

Answer 2

SOLUTION;
(20x+45y) (20x-45y) ans.