Question

Tell me the HCFof391,425,527 in. division methods​

Answer 1

The HCF of 391, 425 and 527 is 17.

Step-by-step explaination:

Factor form of each number are,

391 = 17 × 23

425 = 5 × 5 × 17

527 = 17 × 21

Therefore,

HCF of 391, 425 and 527 is 17.

$\rule{200}{3}$

Answer 2

$\sf{\underline{\huge{\boxed{\purple{\mathfrak{Solution}}}}}}$

• largest no. = 527
• smallest no. = 391

now we will divide the largest and the smallest no.

391 ) 527 ( 1

⠀⠀⠀ - 391

____________

⠀⠀⠀136 ) 391 ( 1

⠀⠀⠀⠀⠀⠀-136

_____________

⠀⠀⠀⠀⠀⠀119) 136 ( 1

⠀⠀⠀⠀⠀⠀⠀⠀- 119

________________

⠀⠀⠀⠀⠀⠀⠀⠀ 17 ) 119 ( 7

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀- 119

__________________

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ 0

• HCF of 391 , 527 = 17
• now check weather the 3rd. no. is also divisible by 17 or not

$\\ \implies \sf\dfrac{425}{17}$

$\\ \implies\sf 25$

• 425 is also divisible by 17

$\sf{\bold{\red{\boxed{HCF \: of \: 425 ,\: 527 \: and\: 391 \: is 17 }}}}$

_________________________❤