Question

TELL ME THE SECOUND EQUTION OF MOTION BY GRAPHICAL METHOD PLEZ ANSWER ME ​

Answer 1

HOLA!!!

ANSWER :-

Consider the velocity time graph of an object that moves under uniform acceleration.

Let 's' the distance travelled by the body.

Therefore, from the graph distance travelled(s)= area of the trapezium OABC= area of rectangle OADC + area of triangle ABD

In the above graph equals OA=CD=u and BC=v.

We know that acceleration(a) = change in velocity/time

a=BD/t

BD=at

Therefore, S= area of trapezium OABC = area of rectangle OADC + area of triangle ABD

=OC×OA×1/2+AD×BE

=t×u×1/2×t×at

$s = ut + (1 \div 2)a {t}^{2}$

HOPE IT HELPS UHH #CHEERS