Question

tell me the Section formula internally and externally​

Answer 1

here is ur answer:-

internally of section formula is

{[(mx2+nx1)/(m+n)],[(my2+ny1)/(m+n)]}

externally of section formula is

P={[(mx2-nx1)/(m-n)],[(my2-ny1)/(m-n)]}

i guess it will help you

Answer 2

Answer:

internally: x=  m1x2+m2x1 /m1+m2

               y=m1y2+m2y1/m1+m2

externally: x= m1x2-m2x1/m1-m2

                 y=m1y2-m2y1/m1-m2