Chemistry, asked by Anonymous, 11 months ago

Tell me the solution of this question

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Answers

Answered by Anonymous

Na2CO3 + H2O ->2Na+ + CO3(2-)

Moles of Na2CO3 = 25.3/106

= 0.23

1 Mole of Na2CO3 gives 2 moles Na+

So 0.23 moles give 2× 0.23 = 0.46 moles Na+

Concentration of Na+ = 0.46/0.25

= 1.84

Concentration of CO3 - 0.23/0.25 = 0.92

So Its (C)

aryanm468: Hey I have seen this question somewhere can somebody please remind me where? Is this a previous year question for jee mains?

Anonymous: Yes

aryanm468: Can I plz know which year m preping for jee

Anonymous: 2019

aryanm468: Ohk thnx a lot

Anonymous: Welcome

Answered by sandeepkumar5525

Hi,mate here's your answer-

Na2Co3 +H2O-2Na+C(O3)2

Moles of *Na2Co3***=25.3/0.6

=0.23

1 mole of Na2Co3 gives 2 *mole*** of Na+

*Concentration*** of Na+ =0.46/0.25

=1.84

Concentration of *CO3***=0.23/0.25

=0.92

So, your answer is option (C).

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