tell me this I mark you as brainliest
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b²=(a+c)(a-c)
b²=a(a-c)+c(a-c)
b²=a²-ac+ac-c²
b²=a²-c² (∵ac-ac is cancelled)
a²=b²+c²
by pathagoras theorem
a²=b²+c²
hence it is a right angled triangle
b²=a(a-c)+c(a-c)
b²=a²-ac+ac-c²
b²=a²-c² (∵ac-ac is cancelled)
a²=b²+c²
by pathagoras theorem
a²=b²+c²
hence it is a right angled triangle
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