Question

tell me this question please

Answer 1

hey friend
u'rrrrrrr
answer
        27x^3yz^-3/3x(yz)^3
      = 9x^/y^2z^6

                         i think this is right answer

Answer 2

$27 {x}^{3}y {z}^{ - 3} \div 3x {y}^{3} {z}^{3} \\ 9 {x}^{(3 - 1)} {y}^{1 - 3} {z}^{ - 3 - 3} \\ 9 {x}^{2} {y}^{ - 2} {z}^{ - 6} \\ \binom{9 {x}^{2} }{ {y}^{2} {z}^{6} }$
I hope it helps u