Tell me whether it is right or wrong and how?
(100-100)/(100-100)
=[10^2-(10^2)]/[10(10-10)]
=[(10+10)(10-10)]/[10(10-10)]
[Since, a^2-b^2=(a+b)(a-b)]
=[10+10]/10
=20/10
=2
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Answers
Step-by-step explanation:
The answer is 0 always.
But I want some fun arguments about this question so I am giving this answer.
I want to clash some points to get above answer..(it's for fun only. I know I am wrong but I want to express what I understand the point of view of this question make
1). We all know that any number × 0 is always 0.
So we can take 0×1 or 0×5 or 0*999 or even infinity ×0 is also 0.
2) we can alter our equation in any form until it can not change the real value of equation. Ex. 1 cab be took as 2–1 or 99–98 or even (a+1)-a
3) If there is multiple answer to an equation then we take one solution which will help in obtaining our answer to the question.
Ex. If there is equation like
(a-4)(a-7)=0 we take either a= 4 or a=7. In which we take only what will help to solve the total problem.
From the above 3 points. I strongly agree that in his point of view he wants to reach his answer 2. He took 0×1=0 and divided 0 with 1 time. Is there is no wrong if I took 0*6=0 and slovenija equation like (10+10)6/10=>120/10=>12.for this answer there is infinity answers are there but he took only way possible to get answer 2.
If you want take infinity ×0=0 and slove.
answer will come infinity.