Question

tell only right answer,nothing extra ​

Answer 1

Answer:

Explanation: Given, mass of the object (m1) = 1kg

Mass of the block (m2) = 5kg

Initial velocity of the object (u1) = 10 m/s

Initial velocity of the block (u2) = 0

Mass of the resulting object = m1 + m2 = 6kg

Velocity of the resulting object (v) =?

Total momentum before the collision = m1u1 + m2u2 = (1kg) × (10m/s) + 0 = 10 kg.m.s-1

As per the law of conservation of momentum, the total momentum before the collision is equal to the total momentum post the collision. Therefore, the total momentum post the collision is also 10 kg.m.s-1

Now, (m1 + m2) × v = 10kg.m.s-1

Therefore v= 10/6= 1.66m/s

The resulting object moves with a velocity of 1.66 meters per second.

Hope it helps!