tell the answer.....
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HEY mate here is your answer.
hope it helps you.
^_^
hope it helps you.
^_^
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Anonymous:
is it crrt
Not actually
Yeah the operation will be +
Your method is correct but the over all ans. is wrong
is it
Answered by
1
Problem:
∫(5x/2+2/√x)dx
Apply linearity:
=5/2∫xdx+2∫1/√xdx
Now solving:
∫xdx
∫x^ndx=x^n+1/(n+1 ) with n=1:
=x^2/2
Now solving:
∫1/√xdx
=2√x
5/2∫xdx+2∫1/√xdx
=5x^2/4+4/√x
= ∫(5x2+2√x)dx
=5x^2/4+4√x+C
∫(5x/2+2/√x)dx
Apply linearity:
=5/2∫xdx+2∫1/√xdx
Now solving:
∫xdx
∫x^ndx=x^n+1/(n+1 ) with n=1:
=x^2/2
Now solving:
∫1/√xdx
=2√x
5/2∫xdx+2∫1/√xdx
=5x^2/4+4/√x
= ∫(5x2+2√x)dx
=5x^2/4+4√x+C
HEY mate u did one mistake
integration of 1/root2= rootx/2
check it
my answer is therefore crrt
did u checked
check*
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