Math, asked by Anonymous, 10 months ago

tell the answer fast

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Answered by vvd28

0

Answer:

here, in the figure,

in ΔABD & ΔACD,

AD = AD ( common )

∠ADB = ∠ADC ( AD⊥ BC )

∠BAD = ∠CAD ( AD is the bisector of ∠A )

∴ ΔABD ≅ ΔACD ( ASA congruency )

By CPCT, AB = AC

∴ ΔABC is an isosceles triangle

Hope it helps...

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