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A triangle named ABC make a line as a bisector named AD and it should be perpendicular to BC
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Answer:
AD bisects ∠A and is perpendicular to BC.
To prove : ΔABC is isoceles
Proof :
In ΔABD & ΔADC
∠BAD=∠DAC (∵ D bisects ∠A)
∠ADB=∠ADC
⇒∠ABD=∠ACD
(∵ if two angles in a triangle are equal to two angles in another triangle then the third angle of both the triangles must also be equal)
⇒∠B=∠C
∴ AB=AC (if two angles are equal then the side opposite to the angles will also be equal)
Proved .
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