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I) P(no girl ) = 211/1500
ii) P(1 girl )= 814/1500
iii) P(2 girl) = 475/1500
iv) P(at most one girl) = (211+814)/1500 =1025/1500
v) P(more girls than boys) = 475/1500.
ii) P(1 girl )= 814/1500
iii) P(2 girl) = 475/1500
iv) P(at most one girl) = (211+814)/1500 =1025/1500
v) P(more girls than boys) = 475/1500.
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Given, the total number of families = 1500.
(1) No girl = 211/1500
(2) 1 girl = 814/2500
(3) 2 girls = 475/1500 = 19/60
(4) Atmost one girl = 211/1500 + 814/1500
= 41/60
(5) More girls than boys = 475/1500.
Hope this helps!
(1) No girl = 211/1500
(2) 1 girl = 814/2500
(3) 2 girls = 475/1500 = 19/60
(4) Atmost one girl = 211/1500 + 814/1500
= 41/60
(5) More girls than boys = 475/1500.
Hope this helps!
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