Question

tell the answer
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Answer 1

Answer:

$\huge\pink{Hello}$

Step-by-step explanation:

$\large\blue{Solution:-}$

(i) Given, Ab is a side of a regular hexagon.

So, Angle formed by it on the centre = 360°/6 = 60°.

So, Angle AOB = 60°

NOW,

Angle BOC = 180° - 60° = 120°

Angle BDC = Angle BOC/2 = 120°/2 = 60°

(We know that angle formed in a segment is half of the angle formed at the centre.)

(ii) In Triangle APB,

Angle PAB = 180°- Angle OAB = 180°-60° = 120°

Angle OBP = 90°

Angle ABO = 60°

Angle ABP = 90°-60° = 30°

Angle APB = 180°-120°-30° = 30°

Angle APB = Angle ABP

Hence, APB is an isosceles triangle.

Note: I have left some steps which are understood.

$\large\red{Hope}$$\large\red{it}$$\large\red{helps}$

Answer 2

Answer:

Step-by-step explanation: