Question

tell the answer of 6 ​

Answer 1

6. we have,

x−3y=3x−1=2x−y

Then,

x−3y=3x−1and3x−1=2x−y

x−3y−3x+1=0

−2x−3y+1=0

2x+3y−1=0…… (1)

Now,

3x−1=2x−y

3x−1−2x+y=0

x+y−1=0 …… (2)

By equation (1) and (2) to and we get,

2x+3y−1=0

(x+y−1=0)×2

Subtracting we get,

y+1=0

y=−1

Put the value of y in equation (2) and we get,

x=2

Hence, (x,y)=(2,−1) is the answer.