Question

Tell the answer of ques 11 with working

Answer 1

Hey

Here is your answer,

Let's look at the prime factors of the divisors:
12 = 2*2*3
16 = 2*2*2*2
24 = 2*2*2*3
28 = 2*2*7
36 = 2*2*3*3

So, the smallest number divisible by 12, 16, 24, 28 and 36 is
= (at least four multiples of 2's)*x(at least two multiples of 3's)x(at least one multiple of 7)
= (2 x 2 x 2 x 2)(3 x 3)(7)
= 1008

The greatest 4-digit number available is 9999.

9999/1008 = 9.9196...
[NOTE: The quotient is 9, while the remainder is 1008x0.9196.. ]

Therefore, the greatest 4-digit number divisible by 12, 16, 24, 28 and 36 is
= 9x1008
= 9072

Hope it helps you!