Math, asked by drsandipbhavar, 2 months ago

tell the answer of this . correct one . i will mark him / her brainiest . plz give explanation​

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Answered by ImperialGladiator
3

Answer:

Son's age = 20 years

Father's age = 40 years.

Explanation :

Question says that,

Son's age is ½ of his father's age.

10 years ago, father was thrice the age of his son.

Find their present age.

Let's take present of father as x years.

Then, son's age would be (½ of x) years.

10 years ago their age :

  • Father's = (x - 10) years.
  • Son = (x/2 - 10) years.

Now,

Father is thrice the age of son.

According to the question :

→ 3(x/2 - 10) = (x - 10)

Solving for x -

→ 3*(x - 20)/2 = (x - 10)

→ 3x - 60/2 = (x - 10)

→ 3x - 60 = 2x - 20

→ 3x - 2x = 60 - 20

→ x = 40

The value of x is 40

Hence, their age of :

  • Father = x = 40 years.
  • Son = ½ of 40 = 20 years.
Answered by Anonymous
3

Answer:

let the present age= x

so according to the question

father's age is x-10

son's age is x/2-10

so father's age is thrice the son's age

so

(x-10)=3(x/2-10)

x-10 = 3x-60/2

2(x-10)=3x-60

2x-20=3x-60

x=40

father's age=40

son's age=20

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