Question

tell the answer please​

Answer 1

Answer:

1/9,1/5,1/12,1/7,1/50,1/7,1/17,1/23

Step-by-step explanation:

hope it can help you

Answer 2

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$\huge\purple{1}$$\huge\red\star{Given ↓}$

$\frac{1}{12}$ , $\frac{1}{23}$ , $\frac{1}{5}$ , $\frac{1}{7}$ , $\frac{1}{50}$ , $\frac{1}{9}$ and $\frac{1}{17}$

$\huge\green\star{Find ↓}$

Arrange the following in ascending and descending order ?

$\huge\red\star{Solution ↓}$

First we all to take the L.C.M of 12 , 23 , 5 , 7 , 50 , 9 and 17 are :-

2² × 3² × 5⁵ × 7¹ × 17¹ × 23¹ $\longrightarrow$ 2,463,300 .

Let's start to find the same denominator :-

$\huge\blue{ \frac{1}{12}}$ => $\frac{1 × 205,275}{12 × 205,275}$ = $\frac{205,275}{2,463,300}$

$\huge\purple{ \frac{1}{23}}$ => $\frac{1 × 107,100}{23× 107,100}$ = $\frac{107,100}{2,463,300}$

$\huge\green{ \frac{1}{5}}$ => $\frac{1 × 492,660}{5× 492,660}$ = $\frac{492,660}{2,463,300}$

$\huge\red{ \frac{1}{7}}$ => $\frac{1 × 351,900}{7 × 351,900}$ = $\frac{351,900}{2,463,300}$

$\huge\purple{ \frac{1}{50}}$ => $\frac{1 × 49,266}{50× 49,266}$ = $\frac{49,266}{2,463,300}$

$\huge\red{ \frac{1}{9}}$ => $\frac{1 × 273,300}{9× 273,300}$ = $\frac{273,300}{2,463,300}$

$\huge\green{ \frac{1}{17}}$ => $\frac{1 × 149,900}{17 × 149,900}$ = $\frac{149,900}{2,463,300}$

Ascending order :-

$\frac{1}{50}$ , $\frac{1}{23}$ , $\frac{1}{17}$ , $\frac{1}{12}$ , $\frac{1}{9}$ , $\frac{1}{7}$ and $\frac{1}{5}$ .

Descending order :-

$\frac{1}{5}$ , $\frac{1}{7}$ , $\frac{1}{9}$ , $\frac{1}{12}$ , $\frac{1}{17}$ , $\frac{1}{23}$ and $\frac{1}{50}$ .

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$\huge\purple{2}$$\huge\red\star{Given ↓}$

$\frac{3}{7}$ , $\frac{3}{11}$ , $\frac{3}{5}$ , $\frac{3}{2}$ , $\frac{3}{13}$ , $\frac{3}{4}$ and $\frac{3}{17}$

$\huge\green\star{Find ↓}$

Arrange the following in ascending and descending order ?

$\huge\red\star{Solution ↓}$

First we all to take the L.C.M of 7 , 11 , 5 , 2 , 13 , 4 and 17 are :-

2² × 5¹ × 7¹ × 11¹ × 13¹ × 17¹ $\longrightarrow$ 340,340 .

Let's start to find the same denominator :-

$\huge\purple{ \frac{3}{7}}$ => $\frac{3 × 48,620}{7 × 48,620}$ = $\frac{145,860}{340,340}$

$\huge\blue{ \frac{3}{11}}$ => $\frac{3 × 30,940}{11 × 30,940}$ = $\frac{92,820}{340,340}$

$\huge\green{ \frac{3}{5}}$ => $\frac{3 × 68,068}{5× 68,068}$ = $\frac{204,204}{340,340}$

$\huge\red{ \frac{3}{2}}$ => $\frac{3 × 170,170}{2 × 170,170 }$ = $\frac{510,510}{340,340}$

$\huge\blue{ \frac{3}{13}}$ => $\frac{3 × 26,180}{13× 26,180}$ = $\frac{78,540}{340,340}$

$\huge\green{ \frac{3}{4}}$ => $\frac{3 × 85,085}{4 × 85,085}$ = $\frac{255,255}{340,340}$

$\huge\blue{ \frac{3}{17}}$ => $\frac{3 × 20,020}{17 × 20,020}$ = $\frac{60,060}{340,340}$

Ascending order :-

$\frac{3}{17}$ , $\frac{3}{13}$ , $\frac{3}{11}$ , $\frac{3}{7}$ , $\frac{3}{5}$ and $\frac{3}{4}$ .

Descending order :-

$\frac{3}{4}$ , $\frac{3}{5}$ , $\frac{3}{7}$ , $\frac{3}{11}$ , $\frac{3}{13}$ and $\frac{3}{4}$ .

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$\huge\purple{3}$$\huge\red\star{Given ↓}$

$\frac{1}{7}$ , $\frac{3}{7}$ , $\frac{13}{7}$ , $\frac{11}{7}$ and $\frac{7}{7}$

$\huge\green\star{Find ↓}$

Arrange the following in ascending and descending order ?

$\huge\red\star{Solution ↓}$

Ascending order :-

$\frac{1}{7}$ , $\frac{3}{7}$ , $\frac{7}{7}$ , $\frac{11}{7}$ and $\frac{13}{7}$ .

Descending order :-

$\frac{13}{7}$ , $\frac{11}{7}$ , $\frac{7}{7}$ , $\frac{3}{7}$ and $\frac{1}{7}$ .