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Answer:Consider
2
x
−
y
+
2
as equation (i) and
2
x
+
3
y
=
22
as equation (ii)
Subtracting (ii) from (i)
2
x
+
3
y
=
22
−
2
x
+
y
=
2
On solving we get
y
=
6
Putting
y
=
6
in equation (ii) we get ,
2
x
+
18
=
22
Giving
x
=
2
∴
x
=
2
and
y
=
6
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