Math, asked by rishabhsharma2540, 4 days ago

tell the answer with steps​

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Answered by ravi2303kumar
1

Answer:

\frac{32+2\sqrt{15}}{{13}}

Step-by-step explanation:

\frac{4+\sqrt{5} }{4-\sqrt{3} } + \frac{4-\sqrt{5} }{4+\sqrt{3} }

= \frac{(4+\sqrt{5})\times(4+\sqrt{3}) + (4-\sqrt{5})\times(4-\sqrt{3})  }{(4-\sqrt{3})*(4+\sqrt{3}) }

= \frac{(4^2+4(\sqrt{3}+\sqrt{5})+\sqrt{3}*\sqrt{5} ) + (4^2-4(\sqrt{3}+\sqrt{5})+\sqrt{3}*\sqrt{5} )}{{(4-\sqrt{3})*(4+\sqrt{3}) }}

= \frac{(16+4\sqrt{3}+4\sqrt{5}+\sqrt{15} ) + (16-4\sqrt{3}-4\sqrt{5})+\sqrt{15} )}{{(4^2 -\sqrt{3}^2)}}

= \frac{16+16+\sqrt{15} +\sqrt{15} )}{{(16 -3)}}

= \frac{32+2\sqrt{15}}{{13}}

Answered by sensanchita62
0

Step-by-step explanation:

Hope it helps to you all.

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