Question

Tell the color of the compound formed after reaction with $\sf{NaOH:-}$

1. $\sf{FeSO_4}$
2. $\sf{FeCl_3}$
3. $\sf{Zn(NO_3)_2}$
4. $\sf{Pb(NO_3)_2}$
5. $\sf{CuSO_4}$
6. $\sf{Ca(NO_3)_2}$

Correct Answers needed.
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Answer 1

Topic :-

• Analytical Chemistry.

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Question :-

Tell the color of the compound formed after reaction with $\sf{NaOH:-}$

$\\ \sf1. {FeSO_4}\\ \sf 2. {FeCl_3}\\ \sf3. {Zn(NO_3)_2}\\ \sf4. {Pb(NO_3)_2}\\ \sf5. {CuSO_4}\\ \sf6. {Ca(NO_3)_2}$

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Answer :-

1. Colour of $\sf{FeSO_4}$ is Green. After reaction with $\sf{NaOH}$, the colour changes to Dirty Green and also forms a precipitate.

$\sf{FeSO_4}\rightarrow\sf{Fe(OH)_2}\downarrow$

Change in colour :-

$\sf{FeSO_4 = \bf{Green}}$

$\sf{Fe(OH)_2 = \bf{Dirty \:Green}}$

__________

2. Colour of $\sf{FeCl_3}$ is Yellow. After reaction with $\sf{NaOH}$, the colour changes to Reddish-Brown and also forms a precipitate.

$\sf{FeCl_3}\rightarrow\sf{Fe(OH)_3}\downarrow$

Change in colour :-

$\sf{FeCl_3 = \bf{Yellow }}$

$\sf{Fe(OH)_3 = \bf{Reddish-Brown}}$

__________

3. Colour of $\sf{Zn(NO_3)_2}$ is Colourless. After reaction with $\sf{NaOH}$, the colour changes to Gelatinous/Dirty White and also forms a precipitate.

$\sf{Zn(NO_3)_2}\rightarrow\sf{Zn(OH)_2}\downarrow$

Change in colour :-

$\sf{Zn(NO_3)_2 = \bf{Colourless}}$

$\sf{Zn(OH)_2 = \bf{Gelatinous/Dirty\:White}}$

__________

4. Colour of $\sf{Pb(NO_3)_2}$ is Colourless. After reaction with $\sf{NaOH}$, the colour changes to Chalky White and also forms a precipitate.

$\sf{Pb(NO_3)_2}\rightarrow\sf{Pb(OH)_2}\downarrow$

Change in colour :-

$\sf{Pb(NO_3)_2 = \bf{Colourless}}$

$\sf{Pb(OH)_2 = \bf{Chalky \:White}}$

__________

5. Colour of $\sf{CuSO_4}$ is Blue. After reaction with $\sf{NaOH}$, the colour changes to Pale Blue and also forms a precipitate.

$\sf{CuSO_4}\rightarrow\sf{Cu(OH)_2}\downarrow$

Change in colour :-

$\sf{CuSO_4 = \bf{Blue}}$

$\sf{Cu(OH)_2 = \bf{Pale \:Blue}}$

__________

6. Colour of $\sf{Ca(NO_3)_2}$ is Colourless. After reaction with $\sf{NaOH}$, the colour changes to White and also forms a precipitate and is sparingly soluble.

$\sf{Ca(NO_3)_2}\rightarrow\sf{Ca(OH)_2}\downarrow$

Change in colour :-

$\sf{Ca(NO_3)_2 = \bf{Colourless}}$

$\sf{Ca(OH)_2 = \bf{White}}$

__________

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Final Answers :-

The resulting colours of compounds after the reaction with $\sf{NaOH:-}$

1. Dirty Green
2. Reddish-Brown
3. Gelatinous/Dirty White
4. Chalky White
5. Pale Blue
6. White

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Answer 2

1.Dirty Green

2.Reddish Brown

3.Dirty White

4.White

5.Blue

6.White

$\Large\bold\purple{THANKS}$